A bacterium divides every 35 minutes. If a cu | vedclass

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(D) The bacterium divides every $35$ minutes. Given total time = $175$ minutes. Number of divisions $(n)$ = $\frac{175}{35} = 5$. Since one bacterium

Vedclass · Accepted Answer

$32 	imes 10^5$ cells/ml

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(D) The bacterium divides every $35$ minutes. Given total time = $175$ minutes. Number of divisions $(n)$ = $\frac{175}{35} = 5$. Since one bacterium produces two cells per division (binary fission),the population grows exponentially according to the formula $N_t = N_0 	imes 2^n$,where $N_0$ is the initial concentration and $n$ is the number of divisions. Initial concentration $(N_0)$ = $10^5$ cells/ml. Final concentration $(N_t)$ = $10^5 	imes 2^5 = 10^5 	imes 32 = 32 	imes 10^5$ cells/ml.

Column-$I$	Column-$II$
$(a)$ Unisexual	$(1)$ Ovum
$(b)$ Bisexual	$(2)$ Syngamy
$(c)$ Fertilization	$(3)$ Monoecious
$(d)$ Female gamete	$(4)$ Dioecious

$A$ bacterium divides every $35$ minutes. If a culture containing $10^5$ cells/ml is grown for $175$ minutes,what will be the cell concentration/ml after $175$ minutes?

Similar Questions

Match the following columns and select the correct option:

Column-$I$ Column-$II$

$(a)$ Unisexual $(1)$ Ovum

$(b)$ Bisexual $(2)$ Syngamy

$(c)$ Fertilization $(3)$ Monoecious

$(d)$ Female gamete $(4)$ Dioecious

Explain the senescence phase.

Is there any relationship between the size of an organism and its lifespan? Give two examples to support your answer.

What is maintained in organisms through the process of reproduction?

Which type of reproduction occurs in $Amoeba$ under unfavorable conditions?

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